-4y^2-25-20y=0

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Solution for -4y^2-25-20y=0 equation: 



-4y^2-25-20y=0

a = -4; b = -20; c = -25;
Δ = b2-4ac
Δ = -202-4·(-4)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{20}{-8}=-2+1/2$

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